Two equal negative charges – q are fixed at points (0,-a) and (0,a) on the y-axis. A positive charge Q is released from rest at the point (2a, 0) on the x-axis. The charge Q will (A) Execute simple harmonic motion about the origin (B) Move to the origin and remain at rest (C) Move to infinity (D) Execute oscillatory but not simple harmonic motion

 The correct answer is (D) Execute oscillatory but not simple harmonic motion


Motion is simple harmonic only if the charge Q is released from a point not very far from the origin on the x-axis.

Else where, motion is periodic but not simple harmonic. 

The motion of Charged Particle in Electric Field

If a charged particle of charge Q is placed in an electric field of strength E, the force experienced by the charged particle = EQ.

  • The acceleration of the charged particle in the electric field, a = EQ/m.
  • The velocity of the charged particle after time t is = (EQ/m)t if the initial velocity is zero.
  • The distance travelled by the charged particle is S = (1/2) × at2 = 1/2(EQ/m) × t2 if the initial velocity is zero.

Getting Info...
Cookie Consent
We serve cookies on this site to analyze traffic, remember your preferences, and optimize your experience.
It seems there is something wrong with your internet connection. Please connect to the internet and start browsing again.
AdBlock Detected!
We have detected that you are using adblocking plugin in your browser.
The revenue we earn by the advertisements is used to manage this website, we request you to whitelist our website in your adblocking plugin.
Site is Blocked
Sorry! This site is not available in your country.