If momentum of an object is increased by 10% then its kinetic energy will increase by?

 Answer: 21%

The relationship between the kinetic energy and momentum of a body is K.E=P2/2m.

Given that, if momentum is increased by 10%, then by what % the K.E will increase. So, the initial momentum be P and initial kinetic energy be K.E=P2/2m.

Increase in momentum = 10% of P, i.e.

⇒10/100×P =P/10 So, final momentum = initial momentum + increased momentum.

Final momentum, P1 = P + P/10 =11P/10. Then, final kinetic energy,

⇒K.E= (P1)2/2m

We have final momentum = 11P/10, putting this value,

we get ⇒K.E1=(11P/10)2/2m = 121P2/2m×100

⇒K.E1=121/100 × P2/2m = 121/100 K.E.

Now, increase in kinetic energy = final kinetic energy – initial kinetic energy. increase in kinetic energy =121/100K.E − K.E

increase in kinetic energy =121K.E−100K.E/100

increase in kinetic energy =21K.E/100

% increase in kinetic energy. ⇒21%

Hence, we can see that if the momentum of an object increases by 10%, then the kinetic energy will increase by 21%.

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