If a magnet is suspended at an angle of 30º to the magnetic meridian, the dip needle makes an angle of 45º with the horizontal. The real dip is________

**Given**

The angle of dip is δ = 45º

The magnet is suspended Θ =30º

**Find out**

We have to determine the real dip

**Solution**

We know that

tanδ ‘ = tan δ / cosΘ

= tan 45/ cos 30

On substituting the values of tan and cos we get

tanδ ‘ = 1 / √3/2

= 2/√3

Real dip = tan-1 ( 2/√3)

**Answer**

If a magnet is suspended at an angle of 30º to the magnetic meridian, the dip needle makes an angle of 45º with the horizontal. The real dip is tan-1 ( 2/√3)