A block of mass 2 kg is placed on the floor (μ = 0.4). a horizontal force of 7 n is applied on the block. the force of friction between the block and floor is

 The mass of the block as given in the question is 2kg.

The coefficient of static friction is 0.4.

Force applied on the block is Fnet = 2.8N

The force of friction between the block and the floor =?

Limitng friction =μN = 0.4 × 2 × 10 = 8N

As applied force is less than limiting friction

so Force of friction on block=Applied external force=7N

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