Question

# Find the greatest number that will divide that will divide 43, 91 and 183 so as to leave the same remainder in each case.

Medium

Solution

Verified by GMS

Question

Medium

Solution

Verified by GMS

Subtract smallest number from both the highest numbers.

we have three cases :

$183>43$ ; $183>91$ and $91>43$

$183−43=140$

$183−91=92$ and

$91−43=48$

Now , we have three new numbers : $140,48$ and $92$

For HCF of $140,48$ and $92$ using prime factorization method, we get

HCF $(140,48$ and $92)=4$

the highest number that divide $183,91$ and $43$ and leave the same remainder is $4.$

Getting Info...

Cookie Consent

We serve cookies on this site to analyze traffic, remember your preferences, and optimize your experience.

AdBlock Detected!

We have detected that you are using adblocking plugin in your browser.

The revenue we earn by the advertisements is used to manage this website, we request you to whitelist our website in your adblocking plugin.

The revenue we earn by the advertisements is used to manage this website, we request you to whitelist our website in your adblocking plugin.

Site is Blocked

Sorry! This site is not available in your country.